b^2+b-15=5

Solution for b^2+b-15=5 equation:

Simplifying
b2 + b + -15 = 5

Reorder the terms:
-15 + b + b2 = 5

Solving
-15 + b + b2 = 5

Solving for variable 'b'.

Reorder the terms:
-15 + -5 + b + b2 = 5 + -5

Combine like terms: -15 + -5 = -20
-20 + b + b2 = 5 + -5

Combine like terms: 5 + -5 = 0
-20 + b + b2 = 0

Factor a trinomial.
(-5 + -1b)(4 + -1b) = 0

Subproblem 1
Set the factor '(-5 + -1b)' equal to zero and attempt to solve:

Simplifying
-5 + -1b = 0

Solving
-5 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + -1b = 0 + 5

Combine like terms: -5 + 5 = 0
0 + -1b = 0 + 5
-1b = 0 + 5

Combine like terms: 0 + 5 = 5
-1b = 5

Divide each side by '-1'.
b = -5

Simplifying
b = -5
Subproblem 2
Set the factor '(4 + -1b)' equal to zero and attempt to solve:

Simplifying
4 + -1b = 0

Solving
4 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1b = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1b = 0 + -4
-1b = 0 + -4

Combine like terms: 0 + -4 = -4
-1b = -4

Divide each side by '-1'.
b = 4

Simplifying
b = 4
Solution
b = {-5, 4}